(4x+14)(2x-4)=8x^2+10x-7

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Solution for (4x+14)(2x-4)=8x^2+10x-7 equation: 



(4x+14)(2x-4)=8x^2+10x-7

We move all terms to the left:

(4x+14)(2x-4)-(8x^2+10x-7)=0

We get rid of parentheses

-8x^2+(4x+14)(2x-4)-10x+7=0

We multiply parentheses ..

-8x^2+(+8x^2-16x+28x-56)-10x+7=0

We get rid of parentheses

-8x^2+8x^2-16x+28x-10x-56+7=0

We add all the numbers together, and all the variables

2x-49=0

We move all terms containing x to the left, all other terms to the right

2x=49

x=49/2

x=24+1/2

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